26x^2-41x-76=0

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Solution for 26x^2-41x-76=0 equation:



26x^2-41x-76=0
a = 26; b = -41; c = -76;
Δ = b2-4ac
Δ = -412-4·26·(-76)
Δ = 9585
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{9585}=\sqrt{9*1065}=\sqrt{9}*\sqrt{1065}=3\sqrt{1065}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-41)-3\sqrt{1065}}{2*26}=\frac{41-3\sqrt{1065}}{52} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-41)+3\sqrt{1065}}{2*26}=\frac{41+3\sqrt{1065}}{52} $

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